22=42x-4.9x^2

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Solution for 22=42x-4.9x^2 equation:



22=42x-4.9x^2
We move all terms to the left:
22-(42x-4.9x^2)=0
We get rid of parentheses
4.9x^2-42x+22=0
a = 4.9; b = -42; c = +22;
Δ = b2-4ac
Δ = -422-4·4.9·22
Δ = 1332.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-42)-\sqrt{1332.8}}{2*4.9}=\frac{42-\sqrt{1332.8}}{9.8} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-42)+\sqrt{1332.8}}{2*4.9}=\frac{42+\sqrt{1332.8}}{9.8} $

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